Campo Arrecho is one of the Colombia city. It is located at the longitude of -74.044845 and latitude of 7.114795. Cienaga De Sabalo Viejo is a Colombia city located at the longitude of -74.032615 and latitude of 7.152585 . The total distance between Campo Arrecho and Cienaga De Sabalo Viejo is 4 KM (kilometers) and 414.64 meters. The mile based measurement distance is 2.7 miles
Campo Arrecho direction from Cienaga De Sabalo Viejo:Campo Arrecho is located nearly south side to Cienaga De Sabalo Viejo.
Travel duration from Campo Arrecho to Cienaga De Sabalo Viejo is around 0.09 Hours if your travel speed is 50 KM per Hour. Cienaga De Sabalo Viejo travelers are welcome to visit our travel driving direction page for detail information with road map. Traveling from Campo Arrecho to Cienaga De Sabalo Viejo is connected by more than one route. Soon you may expect those various travel routes to reach Cienaga De Sabalo Viejo.
campo_arrecho travel guide provides the travel distance guide from campo_arrecho and the following cities; .
Campo Arrecho to Cienaga De Sabalo Viejo fuel cost can be calculated using our fuel cost calculator. It is calculated based on the kilometer and your vehicle fuel consumption per mileage
You are welcome to use our Campo Arrecho to Cienaga De Sabalo Viejo road map and travel planning tool to assist your travel. It shows surrounding tourist places and important places. If there is a bus route between Campo Arrecho to Cienaga De Sabalo Viejo, you can check our bus route map. Campo Arrecho weather and Cienaga De Sabalo Viejo weather is also vaialble at our weather map. Campo Arrecho elevation and Cienaga De Sabalo Viejo altitude available in elevation map.