Cienaga De Sabalo Viejo is one of the Colombia city. It is located at the longitude of -74.032615 and latitude of 7.152585. Campo Arrecho is a Colombia city located at the longitude of -74.044845 and latitude of 7.114795 . The total distance between Cienaga De Sabalo Viejo and Campo Arrecho is 4 KM (kilometers) and 414.64 meters. The mile based measurement distance is 2.7 miles
Cienaga De Sabalo Viejo direction from Campo Arrecho:Cienaga De Sabalo Viejo is located nearly north side to Campo Arrecho.
Travel duration from Cienaga De Sabalo Viejo to Campo Arrecho is around 0.09 Hours if your travel speed is 50 KM per Hour. Campo Arrecho travelers are welcome to visit our travel driving direction page for detail information with road map. Traveling from Cienaga De Sabalo Viejo to Campo Arrecho is connected by more than one route. Soon you may expect those various travel routes to reach Campo Arrecho.
cienaga_de_sabalo_viejo travel guide provides the travel distance guide from cienaga_de_sabalo_viejo and the following cities; .
Cienaga De Sabalo Viejo to Campo Arrecho fuel cost can be calculated using our fuel cost calculator. It is calculated based on the kilometer and your vehicle fuel consumption per mileage
You are welcome to use our Cienaga De Sabalo Viejo to Campo Arrecho road map and travel planning tool to assist your travel. It shows surrounding tourist places and important places. If there is a bus route between Cienaga De Sabalo Viejo to Campo Arrecho, you can check our bus route map. Cienaga De Sabalo Viejo weather and Campo Arrecho weather is also vaialble at our weather map. Cienaga De Sabalo Viejo elevation and Campo Arrecho altitude available in elevation map.